Question

The conversion achieved for the liquid phase reaction occurring in an adiabatic PFR with a heat of reaction -100 kJ/molK, specific heat of the stream being 100 J / molK and the temperature difference being 800K is ___

(a) 0.65

(b) 0.75

(c) 0.90

(d) 0.80

Answer 1

Right choice is (d) 0.80

To explain I would say: XA = (frac{100 × 800}{100000}) = 0.8.