Question

The exit age distribution as a function of time is ____

(a) E = (frac{t^{N-1}}{τ^N}frac{N^N}{(N-1)!}e^frac{-tN}{τ})

(b) E = (frac{t^{N-1}}{τ^N}frac{N}{(N-1)!}e^frac{-tN}{τ})

(c) E = (frac{t^N}{τ^N}frac{N^N}{(N-1)!}e^frac{-tN}{τ})

(d) E = (frac{t^{N-1}}{τ^2}frac{N^N}{(N-1)!}e^frac{-tN}{τ})

Answer 1

The correct option is (a) E = (frac{t^{N-1}}{τ^N}frac{N^N}{(N-1)!}e^frac{-tN}{τ})

The best explanation: For N tanks in series, the exit age distribution is, E = (frac{t^{N-1}}{τ^N}frac{N^N}{(N-1)!}e^frac{-tN}{τ}.) The number of tanks in series, N = (frac{τ^2}{σ^2}. )