Use app×
QUIZARD
QUIZARD
JEE MAIN 2026 Crash Course
NEET 2026 Crash Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
16.3k views
in Physics by (80.9k points)

A particle with unknown mass and charge moves with constant speed v = 1.9 x 106 m/s as it passes undeflected through a pair of parallel plates, as shown above. The plates are separated by a distance d = 6.0 x 10–3 m, and a constant potential difference V is maintained between them. A uniform magnetic field of magnitude B = 0.20 T directed into the page exists both between the plates and in a region to the right of them as shown. After the particle passes into the region to the right of the plates where only the magnetic field exists, its trajectory is circular with radius r = 0.10 m.

a. What is the sign of the charge of the particle? Check the appropriate space below.

___ Positive ___ Negative ___ Neutral ___ It cannot be determined from this information.

Justify your answer.

b. On the diagram above, clearly indicate the direction of the electric field between the plates.

c. Determine the magnitude of the potential difference V between the plates.

d. Determine the ratio of the charge to the mass (q/m) of the particle.

1 Answer

+1 vote
by (52.5k points)
selected by
 
Best answer

(a) Looking in the region where the particle curves, the LHR gives the proper force direction so it’s a – charge

(b) To counteract the Fb downward, an electric force must point upwards. For a negative charge, an E field down makes an electric force upwards.

(c) Find the E field and use V = Ed to get the V.

Between the plates. … Fe = Fb … Eq = qvB … E = vB … (now sub into V = Ed) …

V = vBd = (1.9x106)(0.2)(6x10–3) = 2300 V

(d) Fnet(C) = mv2/r … qvB = mv2 / r … q/m = v / rB … q/m = (1.9x106) / (0.1)(0.2) = 9.5 x 107 C/kg

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...