Question

If v₀ be the orbital velocity of a satellite in a circular orbit close to the earth's surface and v_e is the escape velocity from the earth, then relation between the two is

(a) v₀ = ve

(b) v_e = √3 v₀

(c) v_e = √2 v₀

(d) v_e = 2 v₀

Answer 1

Correct option (c) v_e = √2 v₀

Explanation :

Orbital velocity of satellite = v₀ and escape velocity from the earth = v_e.

orbital velocity (v₀) = √(gR)

and escape velocity (ve) = √(2gR)

Therefore ratio of orbital velocity to escape velocity