Question

For the circuit shown in figure below, the value of Norton’s resistance is _________

(a) 100 Ω

(b) 136.4 Ω

(c) 200 Ω

(d) 272.8 Ω

Answer 1

The correct option is (a) 100 Ω

The explanation: IX = 1 A, VX = Vtest

Vtest = 100(1-2IX) + 300(1-2IX – 0.01VS) + 800

Or, Vtest = 1200 – 800IX – 3Vtest

Or, 4Vtest = 1200 – 800 = 400

Or, Vtest = 100V

∴ RN = (frac{V_{test}}{1}) = 100 Ω.