Question

The current I in the circuit given below is ________

(a) (frac{1}{4}) A

(b) (frac{5}{4}) A

(c) (frac{3}{4}) A

(d) (frac{1}{2}) A

Answer 1

Right answer is (b) (frac{5}{4}) A

Explanation: Using Superposition Theorem, we can write

I = (frac{24}{3+2} – frac{72}{3+2} – frac{3I}{3+2} )

Or, I = 2 – (frac{3I}{3+2})

Or, I = 2 – (frac{3I}{5})

∴ I = (frac{5}{4}) A.