Right answer is (d) IC = 12.732 mA; IL = 12.732 mA
To explain: Resonant Frequency, f = (frac{1}{2πsqrt{LC}} )
= (frac{1}{6.28sqrt{(100×10^{-6})(162.11×10^{-12})}})
= (frac{1}{6.28sqrt{1.621×10^{-14}}})
= (frac{1}{799×10^{-9}}) = 1.25 MHz.
Inductive Reactance, XL = 2πfL = (6.28) (1.25×10^6)(100×10^-6)
= 785.394 Ω
Capacitive Reactance, XC = (frac{1}{2πfC} = frac{1}{(6.28)(1.25×10^6)(162.11×10^{-12})})
= (frac{1}{1.273×10^{-3}}) = 785.417 Ω.
IC = (frac{V_A}{X_C} )
= (frac{10}{785.417} ) = 12.732 mA
IL = (frac{V_A}{X_L} )
= (frac{10}{785.394} ) = 12.732 mA.