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What is the steady state value of F (t), if it is known that F(s) = (frac{10}{(s+1)(s^2+1)})?

(a) -5

(b) 5

(c) 10

(d) Cannot be determined

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Right answer is (d) Cannot be determined

Explanation: The steady state value of this Laplace transform is cannot be determined since; F(s) is having two poles on the imaginary axis (j and –j). Hence the answer is that it cannot be determined.

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