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Refer to Q9 and answer what is the enthalpy change for the reaction of 100.0 g of nitrogen with excess oxygen?

(a) 1164 kJ

(b) 1190 kJ

(c) 1194 kJ

(d) 1160 kJ

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Correct option is (a) 1164 kJ

The best I can explain: Here, we need to convert grams of N2 to moles of N2 and use the conversion factor 180.6 kJ/1 mol N2.

180.6 kJ × (1 mol N2/28.01 g N2) × (180.6 kJ/1 mol N2) = 1164 kJ.

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