Right option is (d) Continuity equation
For explanation: Continuity equation is used as given below.
(
hofrac{De}{Dt}=
hofrac{partial e}{partial t}+
hovec{V}.
abla e )
But,
(
hofrac{partial e}{partial t}=frac{partial(
ho e)}{partial t}-efrac{partial
ho}{partial t})
And
(
hovec{V}.
abla e=
abla.(
ho evec{V})-e
abla.(
ho vec{V}))
Therefore,
(
hofrac{De}{Dt}=frac{partial(
ho e)}{partial t}-efrac{partial
ho}{partial t}+
abla.(
ho evec{V})-e
abla.(
ho vec{V}))
(
hofrac{De}{Dt}=frac{partial(
ho e)}{partial t}-e(frac{partial
ho}{partial t}+
abla.(
ho vec{V}))+
abla.(
ho evec{V}))
Applying the continuity equation, (frac{partial
ho}{partial t}+
abla.(
ho vec{V})=0), and hence
(
hofrac{De}{Dt}=frac{partial(
ho e)}{partial t}+
abla.(
ho evec{V})).