In ΔABC, given BC = 'a' cm, ∠B = x° and difference of two sides AB and AC is equal to 'b' cm.
Case I: AB > AC
Step 1: Draw the base BC = 'a' cm.
Step 2: Make ∠XBC = x°.
Step 3: Mark a point D on ray BX such that BD = 'b' cm.
Step 4: Join DC.
Step 5: Draw the perpendicular bisector of DC such that, it intersects the ray BX at a point A.
Step 6: Join AC.
Thus, ABC is the required triangle.
Case II: AB < AC
Step 1: Draw the base BC = 'a' cm.
Step 2: Make ∠XBC = x° and extend ray BX in the opposite direction.
Step 3: Mark a point D on the extended ray BX such that BD = 'b' cm.
Step 4: Join DC.
Step 5: Draw the perpendicular bisector of DC such that, it intersects the ray BX at a point A.
Step 6: Join AC.
Thus, ABC is the required triangle.