Question

A tube open at both ends is 47 cm long. Calculate the fundamental frequency of the air column. (Ignore the end correction. Speed of sound in air is 3.3 × 10² m/s.)

Answer 1

Data : L = 47 cm = 0.47 m, v = 330 m/s. 

The fundamental frequency of the air column,

n = \(\frac v{2L}\) = \(\frac{330}{2\times0.47}\) = \(\frac{165}{0.47}\) = 351.1 Hz