Find the limit of the function, if it exists, at x = 1 : f(x) = {(7-4x) for (x<1), (x^2+2) for (x≥1)

Question

Find the limit of the function, if it exists, at x = 1

f(x) = \(\begin{cases} 7-4x&for&x<1\\x^2+2&for&x\geq1 \end{cases} \)

f(x) = {(7-4x) for (x<1), (x²+2) for (x≥1)

Answer 1

f(x) = 7-4x; x<1

= x²+2; x ≥1