Question

If 10 g of ice is added to 40 g of water at 15°C, then the temperature of the mixture is (specific heat of water = 4.2 x 10³ J kg^-1 K^-1, Latent heat of fusion of ice = 3.36 x 10⁵ J kg^-1)

(a) 15°C

(b) 12°C

(c) 10°C

(d) 0°C

Answer 1

Correct option (d) 0°C

Explanation :

Heat lost by 40 g water to come from 15°C to 0°C is

Heat required to convert 10 g ice into l0 g water at 0°C is

Since H₂ > H₁, so the whole ice will not be converted into water, whereas the temperature of the whole water will be 0°C. Therefore the temperature of the mixture is 0°C.