Correct Answer - Option 3 : 45°
Concept:
In a liquid container subjected to a constant acceleration a, having components ax and ay, the slope of the surface of constant pressure is given by,
\(\frac{{dz}}{{dx}} = - \frac{{{a_x}}}{{g + {a_z}}}\)
For constant horizontal acceleration a, the slope of the constant pressure is
\(\tan θ = \frac{{dz}}{{dx}} = - \frac{a}{g}\)
For constant vertical acceleration, the surface of constant pressure are horizontal
\(\tan θ = \frac{{dz}}{{dx}} = 0\)
Explanation:
given,
Horizontal acceleration, ax = g
For constant horizontal acceleration a, the slope of the constant pressure is
\(\tan θ = \frac{{dz}}{{dx}} = - \frac{a}{g}\)
tanθ = g/g = 1
θ = 45°