Concept:
The actual discharge through Hole is given by:
\(Q = {C_d} × A × \sqrt {2gh} \)
where,
Cd is the coefficient of discharge, A is the cross-sectional area of the hole, h is the differential head, g = acceleration due to gravity.
Calculation:
Given:
Cd = 1, A = 5 mm2 = 5 × 10-6, h = 5 m, g = 10 m/s2.
Now, the actual discharge through hole is given by:
\(Q = {C_d} × A × \sqrt {2gh} \)
\(Q = {1} × 5×10^{-6} × \sqrt {2× 10 × 5} \)
\(Q = 5× 10^{-5} \;m^3/sec\)
\(Q = 3.0 \;L/min\) [∵ 1 m3 = 1000 L and 1 min = 60 sec]