Correct Answer - Option 2 : the numerically larger root as positive.
Calculation:
Given the equation, x2 - 2x - 8 =0 ...(1)
As we know, the sum of roots = \(-b\over a\) and, the product of roots = \(c\over a\)
From equation (1), the sum of roots = -(-2)/1 = 2
and, the product of roots = -8
Since the product of the roots is negative ⇒ one of the roots is positive and the other is negative.
Since the sum of the roots is positive ⇒ the positive root is numerically larger than the negative root.
So, The equation x2 - 2x - 8 =0 will have the numerically larger root as positive.
For a quadratic equation of the form, ax2 + bx + c = 0, we can use the following table to determine the sign of the roots of the equation.
Sign of the product of the roots |
Sign of the sum of the roots |
Sign of the roots |
+ ve |
+ ve |
Both the roots are positive. |
+ ve |
- ve |
Both the roots are negative. |
- ve |
+ ve |
The numerically larger root is positive and the other root is negative. |
- ve |
-ve |
The numerically larger root is negative and the other root is positive. |