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in Chemistry by (83.7k points)

Rohan took 10 mL of freshly prepared iron sulphate solution in four different test tubes and added four different metal strips to each test tube as shown below :

ln test tubes I and llI, black residue was obtained while in test tubes ll and lV, no change was observed. Metals P, Q, R and S could be respectively 

(A) Al, Cu, Pb, As

(B) Pb, Cu, Ag, Al 

(C) Zn, Al, Cu, Ag 

(D) Zn, Cu, Al, Ag.

1 Answer

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Best answer

Correct option  (D) Zn, Cu, Al, Ag.

Explanation:

Black residue is obtained in test tubes I and lll i.e., iron gets displaced in test tubes I and lll. Therefore, metals P and R should be more reactive than iron.

No change is observed in test tubes ll and lV hence, metals Q and S should be less reactive than iron.

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