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An equation of a plane parallel to x + 2y + 2z = 5 and at a unit distance from the origin is given by 
1. x + 2y + 2z + 3 = 0
2. x + 2y + 2z + 6 = 0
3. x + 2y + 2z + 4 = 0
4. x + 2y + 2z + 1 = 0

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Correct Answer - Option 1 : x + 2y + 2z + 3 = 0

Concept:

The equation of a plane parallel to plane ax + by + cz + d = 0 is given by ax + by + cz + k = 0;

The distance of point p = (x1, y1, z1) from a plane ax + by + cz + d = 0 is given by

\(d = \frac{{\left| {a{x_1} + b{y_1} + c{z_1} + d} \right|}}{{\sqrt {{a^2} + {b^2} + {c^2}} }}\)

Calculation:

Given equation of a plane parallel to x + 2y + 2z = 5

⇒ equation of plane = x + 2y + 2z + k = 0;

Given unit distance from origin i.e. (0, 0, 0);

\( \Rightarrow 1 = \frac{{\left| k \right|}}{{\sqrt {{1^2} + {2^2} + {2^2}} }}\)

⇒ k = 3 or -3;

The final equation of plane will be

 x + 2y + 2z + 3 = 0 or x + 2y + 2z -3 = 0

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