Question

Methane, the first member of alkane homologous series has the boiling point equal to -161°C. Which of the following iepresents the correct formula and boiling point of third member of the series? 

Molecular formula Boiling point (°C)

Molecular formula	Boiling point (°C)
(A) C3H4	-85
(B) C2H6	-185
(C) C3H6	-69
(D) C3H8	-42

Answer 1

Correct option  (D)

Explanation: 

Third memberof alkane series is propane i.e., C₃H₈. Also, on moving down the series, boiling point goes on increasing hence, its boiling point should be higher than that of methane.