Question

The critical angle for a glass-air interface is sin^-1 5/8 . A ray of unpolarized monochromatic light in air is incident on the glass. What is the polarizing angle?

Answer 1

Data : θ_c = sin^-1 \(\cfrac58\)

∴ sin θ_c = \(\cfrac58\)

∴ n = \(\cfrac1{sin \,θ_c}\) = \(\cfrac85\) = 1.6

Also, n = tan θ_B

∴ θ_B = tan^-1 n

∴ The polarizing angle, θ_B = tan^-1 1.6 = 58°