Question

The potential difference between points x and y in the circuit

Answer 1

\(\frac1{R_{eq}}\) = \(\frac1{80}+\frac1{60}\) 

\(\frac1{R_{eq}}\) = \(\frac{30+40}{2400}\) 

\(\frac1{R_{eq}}\) = \(\frac{70}{2400}\) 

\(R_{eq}=\frac{240}7\) 

\(R_{eq}=34.2 \Omega\)

i = V/R

i = 80/34.2

i = 2.3 ampeare

current will divided equal is 1.15 ampere and 1.15 ampere in parallel

Potential difference at x

V_x = 50 x 1.15

V_x = 57.5 volt

Potential difference at y

V_y = 30 x 1.15

V_y = 34.5 volt

Difference b/w V_x and V_y

V = V_x - V_y

V = 57.5 - 34.5

V = 23 volt