Data : ∆l1 = 7.5 × 10-6 m,
∆l2 = 1.8 × 10-6 m
λ = 6 × 10-7 m
For point P : Let p \(\cfrac λ2\) = ∆l1

The path difference ∆l is an odd integral multiple of λ/2 : ∆l1 = (2m – 1) \(\cfrac λ2\), where m is an integer,
∴ 2m – 1 = 25
∴ m = 13
∴ Point P is at the centre of the 13th dark band.
For point Q :
Let q \(\cfrac λ2\) = ∆l2

The path difference ∆l2 is an even integral multiple of \(\cfrac λ2\) : ∆l2 = (2n) \(\cfrac λ2\), where n is an integer
∴ 2n = 6
∴ n = 3
∴ Point Q is at the centre of the 3rd bright band.
Between points P and Q, excluding the respective bands at P and Q, the number of dark bands = 12 + 3 = 15 and the number of bright bands (including the central bright band) = 12 + 2 + 1 = 15