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If the pth term of an A.P. is q and the qth term is p, prove that its nth term is (p + q - n).

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ap = q => A + (p - 1) D = q ......(i)

& aq = p => A + (q - 1) D = p

Solve (i) & (ii) to get D = - 1 & A = p + q - 1

So, an = A + (n - 1) D

an = (p + q - 1) + (n - 1) (-1) 

an = p + q - n.

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