Correct Answer - Option 1 :
\(\dfrac{1}{2\pi f_0 RC}\)
Concept:
The quality factor is defined as the ratio of the maximum energy stored to maximum energy dissipated in a cycle
\(Q = 2π \frac{{Maximum\;energy\;stored}}{{Total\;energy\;lost\;per\;period}}\)
The quality factor in a series RLC circuit is given by:
\(Q = \frac{1}{R}√ {\frac{L}{C}}\) ----- (1)
When the RLC circuit is set to resonate (XL = XC), the resonant frequency is expressed as
\(f_0 = \frac{1}{{2π }}√ {\frac{1}{{LC}}}\) ----- (2)
Application:
From (2), we can write
√L = 1/( 2π × f0 × √C) ----- (3)
Substitute (3) in (1), we get
Q = [1/( 2π × f0 × √C) ] / (R × √C)
⇒ Q = \(\dfrac{1}{2\pi f_0 RC}\)