Correct Answer - Option 4 : 9 μC
Concept:
\(C = \frac{{{\epsilon_0}{\epsilon_r}A}}{d}\)
Q = CV
\(= \frac{{{\epsilon_0}{\epsilon_r}AV}}{d}\)
Analysis:
Maximum electrical charge on the capacitor,
when,
\(\left( {\frac{V}{d}} \right) = {\left( {\frac{V}{d}} \right)_{max}} = 60 \times kV/cm = 60 \times {10^3} \times {10^2}V/m\)
Q = 8.85 × 10-12 × 3 × 15 × 10-2 × 35 × 10-2 × 60 × 103 × 102
= 8.36 μC