Let AB denote the lamp-post and CD the girl after walking for 4 seconds away from the lamp-post (see Fig. 6.32). From the figure, you can see that DE is the shadow of the girl. Let DE be x metres.
Now, BD = 1.2 m × 4 = 4.8 m.
Note that in ΔABE and ΔCDE,
∠B =∠D (Each is of 90° because lamp-post, as well as the girl, are standing vertical to the ground)
So, the shadow of the girl after walking for 4 seconds is 1.6 m long.