Question

The following program is written for an 8085 microprocessor to add two bytes located at memory addresses IFFE and IFFF.

LXIH,	IFFE
MOV	B, M
INR	L
MOV	A, M
ADD	B
INR	L
MOV	M,A
XOR	A

On completion of the execution of the program, the result of the addition is found 

1. in the register A
2. at the memory address 1000
3. at the memory address IF00
4. at the memory address 2000

Answer 1

Correct Answer - Option 3 : at the memory address IF00

Let the two bytes for addition are 02H that is stored at 1FFE  and 03H that is stored at 1FFF

Now,

LXI H, 1FFE  (H ← 1F, L ← FE)

MOV B, M (B ← 02 H)

INR L (H ← 1F, L ← FF)

MOV A, M (A ← 03 H)

ADD B ( A ← 03H + 02H = 05H)

INR L (H ← 1F, L ← 00)

MOV M, A (1FOO ← 05H)

XOR A (A ← 00H)

The result of the addition is thus stored in at the memory location 1F00