Correct Answer - Option 4 :
\(3:49{1\over 11}\)
The logic follows here is :-
The time between 3 O'Clock and 4 O'Clock when two hands of clock are together is :
Time = \({2\over 11}(30x \pm θ)\)
Where x = starting time and θ = angle of hands
Here x= 3 and θ = 1800
Therefore, Time = \({2\over 11}(30 \times 3 \pm 180^0)\) = \({2\over 11}(270)\) = \({540\over 11}\) = \(49{1\over 11}\)
Time when two hands of clock are together is 3:\(49{1\over 11}\)
Thus, the correct answer is 3:\(49{1\over11}\).