Correct Answer - Option 2 : 10.8%
Given:
A1 = 2.5V, A2 = 0.25V, A3 = 0.1V
\(\begin{array}{l} {D_2} = \frac{{{A_2}}}{{{A_1}}} = 0.1\\ {D_3} = \frac{{{A_3}}}{{{A_1}}} = 0.04\\ THD = \sqrt {D_2^2 + D_3^2 } = \sqrt {{{\left( {0.1} \right)}^2} + {{\left( {0.04} \right)}^2} } \end{array}\)
= 0.1077
= 10.77%