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The direction cosine of a normal to the plane 2x – 3y –6z + 14 = 0 are

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The direction cosine of a normal to the plane 2x – 3y –6z + 14 = 0 are

(A) (2/7,-3/7,-6/7)

(B) (-2/7,-3/7,6/7)

(C) (-2/7,-3/7,-6/7)

(D) None of these

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1 Answer

+1 vote
by (80.9k points)

Correct option:

(A) (2/7,-3/7,-6/7)

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