Correct Answer - Option 1 : 0.2
Concept:
The probability density function of Poisson’s distribution is
\(p\left( x \right)=\frac{{{e}^{-\lambda }}\cdot {{\lambda }^{x}}}{x!}\)
Where
λ = mean = np
n = number of total outcomes
p = probability of success
Note: This distribution uses where the probability of success i.e. p is very small.
Calculation:
Probability (p) = 0.1
λ = mean = 10 × 0.1 = 1
Probability that exactly two will be defective
\( p\left( x \right)=\frac{{{e}^{-1}}\cdot {{\left( 1 \right)}^{2}}}{2!}\)
= 0.184 ≈ 0.2
