Question

When the optical power incident on a photodiode is 10 μW and the responsivity is 0.8 A/W, the photocurrent generated (in μA ) is

Answer 1

Concept:

In a photodiode, the responsivity is given by:

\(R = \frac{I}{P}\)

I = photocurrent generated

P = Optical power incident

R = Responsitivity

Calculation:

Given:

R = 0.8 A/W and P = 10 μW

\(0.8 = \frac{I}{10\mu}\)

I = 0.8 × 10 μA = 8 μA