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A heater element is made of nichrome wire having resistivity equal to 100 × 10-8 Ωm and a diameter of 0.4 mm. The length of the wire required to get a resistance of 40 Ω will be nearly
1. 9 m
2. 7 m
3. 5 m
4. 3 m

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Correct Answer - Option 3 : 5 m

​Concept:

The resistance of a material is given by:

\(R = \frac{{ρ ~l}}{A}\)

R = Resistance of the wire

ρ = resistivity of the material

l = length of wire

A = cross-sectional area of the wire = πr2

\(A=\pi(\frac{d}{2})^2\)

\(R = \frac{ρ l}{\pi(\frac{d}{2})^2}=\frac{4ρ l}{\pi d^2}\)

Calculation:

Given: ρ = 100 × 10-8 Ωm

d =  0.4 mm = 0.4 × 10-3 m

R = 40 Ω, i.e.

\(40=\frac{4\times 100\times 10^{-8}\times l}{\pi (0.4 \times 10^{-3})^2}\)

l = 5.024 m

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