Correct Answer - Option 3 : 0.6
Concept:
For an Amplitude modulated wave with carrier amplitude AC, the maximum and minimum amplitude is given by:
Amax = Ac(1 + μ)
Amin = Ac(1 - μ)
\(\frac{{{A_{max}}}}{{{A_{min}}}} = \frac{{1 + μ}}{{1 - μ}}\)
The above can be written as:
\(μ = \frac{{{A_{max}} - {A_{min}}}}{{{A_{max}} + {A_{min}}}}\)
Calculation:
Given Amax = 160 V and Amin = 40 V
The modulation index will be:
\(μ = \frac{{{160} - 40}}{{160 + 40}}=\frac{120}{200}\)
μ = 0.6
