Question

The transfer function of a zero order hold is given by
1. \(\frac{1}{s}\)
2. 1 – e^-Ts
3. s (1 - e^-Ts)
4. \(\frac{{1 - {e^{ - Ts}}}}{s}\)

Answer 1

Correct Answer - Option 4 : \(\frac{{1 - {e^{ - Ts}}}}{s}\)

The impulse response of the zero-order hold is shown below.

 

From the above response, g(t) = u(t) – u(t – T)

By applying the Laplace transform,

\(G\left( s \right) = \frac{1}{s} - \frac{{{e^{ - Ts}}}}{s}\)

\(=\frac{{1 - {e^{ - Ts}}}}{s}\)