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If the matrix A is such that

\(A = \left[ {\begin{array}{*{20}{c}} 2\\ { - 4}\\ 7 \end{array}} \right]\left[ {1\;\;\;9\;\;\;5} \right]\) 

Then the determinant of A is equal to ____

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Concept:

Determinant of Matrix  \(M = {\left[ {\begin{array}{*{20}{c}} a\\ b\\ :\\ d \end{array}} \right]_{n \times 1}}{\left[ {p\;\;\;q\;\;\;..\;\;s} \right]_{1 \times n\;}}\)  is 0

Calculation:

\(A = {\left[ {\begin{array}{*{20}{c}} 2\\ { - 4}\\ 7 \end{array}} \right]_{3 \times 1}}{\left[ {1\;\;\;9\;\;\;5} \right]_{1 \times 3\;}}\;\) 

\(A = \;{\left[ {\begin{array}{*{20}{c}} 2&{18}&{10}\\ { - 4}&{ - 36}&{ - 20}\\ 7&{63}&{35} \end{array}} \right]_{3 \times 3}}\)

\(\left| A \right| = \;\left| {\begin{array}{*{20}{c}} 2&{18}&{10}\\ { - 4}&{ - 36}&{ - 20}\\ 7&{63}&{35} \end{array}} \right|\)

\(\left| A \right| = \;2 \times - 4 \times 7\left| {\begin{array}{*{20}{c}} 1&9&5\\ 1&9&5\\ 1&9&5 \end{array}} \right|\)

Since 2 rows are identical determinant is 0

\(\left| A \right| = \;2 \times - 4 \times 7 \times 0 = 0\)

The determinant of A is equal to 0

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