Correct Answer - Option 3 : 1/1260
Explanation:
A box contains 2 blue, 3 black, and 4 red balls.
Balls are drawn from the box at random one at a time without replacement.
The probability of drawing 2 blue balls first followed by 3 black balls and subsequently 4 red balls is
\( = \frac{{{2_{{C_1}}}}}{{{9_{{C_1}}}}} \times \frac{{{1_{{C_1}}}}}{{{8_{{C_1}}}}} \times \frac{{{3_{{C_1}}}}}{{{7_{{C_1}}}}} \times \frac{{{2_{{C_1}}}}}{{{6_{{C_1}}}}} \times \frac{{{1_{{C_1}}}}}{{{5_{{C_1}}}}} \times 1\)
\( = \frac{2}{9} \times \frac{1}{8} \times \frac{3}{7} \times \frac{2}{6} \times \frac{1}{5} \times 1 = \frac{1}{{1260}}\)
