Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
130 views
in Physics by (95.2k points)
closed by
The efficiency of a pump is 50%. It lifts 2 tonnes of water by 60 m in 20 minutes. Find the input power (in kW) of the pump.
1. 4
2. 1
3. 2
4. 3

1 Answer

0 votes
by (95.4k points)
selected by
 
Best answer
Correct Answer - Option 3 : 2

The correct answer is 2.

Given,

Mass (m) = 2 tonnes = \(2\times10^3Kg\).

Height (h) = 60 meters.

Acceleration due to gravity (g) = 10 m/s.

Time (t) = 20 minutes = \(20\times60\ seconds\) 

Efficiency = 50% = \({1 \over2}\)

\(Power(Output) = {Work \over Time}\)     ...1)

\(Work= m\times g\times h\)      ...2)

Substitute 2) in 1)

\(Output \ Power = {2\times10^3\times10\times60 \over 20\times60}\)

\(Output\ Power=10^3 watts\)

\(Efficiency = {Output \ Power \over Input\ Power}\)

\({1 \over 2}={10^3\over Input\ Power}\)

\(\therefore\;Input\ Power=2\times10^3 watts = 2\ kW\).

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...