Correct Answer - Option 1 : 0.3 m
2/Vs
Concept:
Conductivity of intrinsic semiconductor is given by:
σr = ni q (μn + μp)
Where, σi = intrinsic conductivity
q = electronic charge = 1.6 × 10-19 C
μn = electron mobility
μp = hole mobility
ni = Intrinsic carrier concentration
Calculation:
Given
σi = 2.32 /Ωm
ni = 2.5 × 1019 / m3
q = 16 × 10-19 C
μn = μp
Let μn = μp = μ
σi = ni q (μn + μp)
2.32 = 2.5 × 1019 × 1.6 × 10-19 (μ + μ)
2.32 = 2.5 × 1.6 × 2μ
μ = 0.29 m2 / V-sec
μ ≃ 0.3 m2 / V-sec