Correct Answer - Option 1 : 1.8 mm
Concept:
The height of Watt governor is
\(H = \frac{{895000}}{{{N^2}}}mm\)
Where, N = speed of governor in RPM.
Calculation:
At, N = 100 rpm
\({H_1} = \frac{{895000}}{{{{100}^2}}} = 89.5\;mm\)
At, N = 101 rpm
\({H_2} = \frac{{895000}}{{{{101}^2}}} = 87.74\;mm\)
∴ Change in height (∆H) is
∆H = H1 − H2
∴ ∆H = 89.5 – 87.74
∴ ∆H = 1.76 mm