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Propyne reacts with sodium in presence of liquid amonia form a compound [A].

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Propyne reacts with sodium in presence of liquid amonia form a compound [A]. Compound [A] reacts with a compound [B] forms 2-butyne. The compound [B] is 

(a) CH3 – OH 

(b) CH3 – Br

(c) C2H5 – Br

(d) CH3 – CHO

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1 Answer

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The compound [B] is CH3 – Br.

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