Correct Answer - Option 2 : Inversely proportional to value of integrating capacitor (C
in) and the frequency of the input (f
in)
The output voltage & ripple voltages of basic frequency to voltage converter is given below:
\({V_{out}} = {f_{in}} \times \left[ {\frac{{{R_L}}}{{{R_s}}}} \right] \times \left( {1.9v} \right) \times \left( {1.1\;{R_t} \cdot {C_t}} \right)\)
Output ripple P.P is given by:
\(\frac{1}{{{C_{in}}}} \times \frac{{\left( {1.9\;v} \right) \times \left( {1.1\;{R_t}\;{C_t}} \right)}}{{{R_s}}}\)
Therefore, the amount of ripple in the output voltage of a frequency to voltage converter is independent of the frequency of input (fin) & inversely proportional to the value of integrating capacitor (Cin)
If we want a quicker response, it is easy to decrease the value of Cin, but the ripple will increase by the same factor.
Most frequency-to-voltage converters suffer from the classical trade-off ripple versus speed of response.