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1 Answer

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Best answer

AB =√(x2-x1)²+(y2-y1

x1 = -a cosΦ, y1 = b sinΦ
x2 = a sinΦ, y2 = -b cosΦ

Put the value in the equation
AB = √(
a sinΦ + a cosΦ)2 + (-b cosΦ - b sinΦ)2
AB = (
sinΦ + cosΦ)√(a2+b2)

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