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A moving coil galvanometer has a coil with 175 turns and area 1 cm2. It uses a torsion band of torsion constant 10-6 N-m/rad. The coil is placed in a magnetic field B parallel to its plane. The coil deflects by 1° for a current of 1 mA. The value of B (in Tesla) is approximately:
1. 10-4
2. 10-2
3. 10-1
4. 10-3

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Correct Answer - Option 4 : 10-3

Concept:

Moment of the deflecting couple:

The moment of the deflecting couple = nBIA

When the coil deflects, the suspension wire is twisted. On account of elasticity, a restoring couple is set up in the wire. This couple is proportional to the twist.

If θ is the angular twist, then, the moment of the restoring couple = Cθ, where C is the restoring couple per unit twist.

At equilibrium, Deflecting couple = Restoring couple

Hence we can write, nBIA = Cθ

Calculation:

Given, Number of turns, N = 175

Area = 1 cm-2 = 10-4 m

Torsional constant, C = 10-6 N-m/rad

Current, I = 1 mA = 10-3 A

Torque is given by,

\(\tau = \vec M \times \vec B\)

On substituting the values in Cθ = NBiA, we get

\({10^{ - 6}}\left( {\frac{\pi }{{180}}} \right) = 175 \times B\left( {{{10}^{ - 3}}} \right) \times {10^{ - 4}}\)

\(B = \frac{{{{10}^{ - 6}} \times \pi }}{{180 \times 175 \times {{10}^{ - 3}} \times {{10}^{ - 4}}}}\)

\(B = \frac{{22}}{7} \times \frac{{10}}{{180 \times 175}} \approx 0.001 \approx 1 \times {10^{ - 3}}\)

∴ B ≈ 10-3 T

Thus, the value of B (in Tesla) approximately is 10-3 T.

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