Correct Answer - Option 1 :
\(C{{H}_{4}}+2{{O}_{3}}\to 3C{{H}_{2}}=O+3{{H}_{2}}~O\)
Concept:
CH4 is not present in the stratosphere and also it cannot diffuse or escape into the stratosphere like freon- 12
(CF2 Cl2) From the atmosphere. In the stratosphere, ozone layer depletion take place mainly by chlorofluorocarbons (CFCs) like CF2 Cl2 and the mechanism of ozone layer depletion can be shown as:
(i) \({\rm{C}}{{\rm{F}}_2}{\rm{C}}{{\rm{l}}_2}\left( g \right)\mathop \to \limits^{{\rm{hv}}} {\rm{C\dot l}}\left( g \right) + \dot C{{\rm{F}}_2}{\rm{Cl}}\left( g \right)\) [option d)]
(ii) \({\rm{C\dot l}}\left( {\rm{g}} \right) + {{\rm{O}}_3}\left( g \right) \to {\rm{Cl}}{{\rm{O}}^.}\left( g \right) + {{\rm{O}}_2}\)
(iii) \({\rm{Cl}}{{\rm{O}}^.}\left( g \right) + {\rm{O}}\left( g \right) \to {\rm{Cl}}{{\rm{O}}^.}\left( g \right) + {{\rm{O}}_2}\) [option d]
(iv) \(C\dot l\left( g \right) + {H_2}O\;\left[ {present\;in\;the\;stratosphere} \right] \to HOCl\left( g \right) + {H^.}\left( g \right)\)
(v) \(HOCl\left( g \right)\mathop \to \limits^{hv} \;\dot OH\left( g \right) + C{l^.}\left( g \right)\) [option c]
⇒ One Cl. can destroy or deplete 105 O3 molecule.
As (i) reaction is involved in the formation of photochemical smog, not in ozone layer depletion. So, option (a) is correct.