Question

For the following reaction, the mass of water produced from 445 g of C₅₇ H₁₀ O₆ (g) is

2C₅₇ H₁₁₀ O₆ (s) + 163O₂ (g) → 114CO₂ (g) + 110H₂O (l)
1. 490 g
2. 445 g
3. 495 g
4. 890 g

Answer 1

Correct Answer - Option 3 : 495 g

The given reaction is

2C₅₇H₁₁₀O₆ (g) + 163O₂ (g) → 114CO₂ (g) + 110H₂O (l)

The molecular mass of the given compound is C₅₇ H₁₀ O₁₆

The atomic mass of carbon is 12 and

The atomic mass of Hydrogen is 1

The atomic mass of Oxygen is 6

Mass of the water produced from 445 g of C₅₇ H₁₁₀ O₆ (g) = 2 × (12 × 57 × 1 × 110 × 16 × 6)g

= 1780 g

The molecular mass of the H₂O = 110 (2 + 16) = 1980 g

1780 g of C₅₇ H₁₁₀ O₆ produced = 1980 g of H₂ O

445 g of C₅₇ H₁₀ O₆ produced = \(\frac{{1980}}{{1780{\rm{\;}}}}\) × 445 g of H₂O

= 495 of H₂O