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The Boolean expression \(\left( {x + y} \right)\left( {x + \bar y} \right) + \overline {\left( {x\bar y} \right) + \bar x} \) simplifies to
1. x
2. y
3. xy
4. x + y

1 Answer

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Best answer
Correct Answer - Option 1 : x

Concept:

De Morgan’s law states that:

\(\overline {\left( {{A_1}\;.\;{A_2} \ldots \;{A_n}} \right)} \; = \left( {\overline {{A_1}} \; + \;\overline {{A_2}} \; + \; \ldots \; + \;\overline {{A_n}} } \right)\;\)

\(\overline {\left( {{A_1}\; + \;{A_2}\; + \; \ldots \; + \;{A_n}} \right)} \; = \left( {\overline {{A_1}} \;.\;\overline {{A_2}} \;.\;..\;\overline {{A_n}} } \right)\)

Analysis:

\(\left( {x + y} \right)\left( {x + \bar y} \right) + \overline {\left( {x\bar y} \right) + \bar x} \)

\(= xx + x\bar y + xy + y\bar y + \left( {\overline {x\bar y} \;.\overline{\overline x} } \right)\)

= x + xy̅ + xy + (x̅ + y) (x)

= x + xy

= x

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