Correct Answer - Option 4 : 4
f(–x) = –f(x) = g(x)
∴ f(x) . g(x) = – {f(x)}2
or f(1) . g(1) = –{f(1)}2
= \(-{\left| {\begin{array}{*{20}{c}} 1&1&1\\ 0&2&1\\ 1&3&1 \end{array}} \right|^2}\)
Applying R3 → R3 – R1 ls , then rc
f(1) . g(1) = \(-{\left| {\begin{array}{*{20}{c}}
1&1&1\\
0&2&1\\
0&2&0
\end{array}} \right|^2}\) = –(0 – 2)2 = – 4