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There are 12 points in a plane of which 5 are collinear. Barring these five points no three are collinear. The number of quadrilaterals one can form u

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There are 12 points in a plane of which 5 are collinear. Barring these five points no three are collinear. The number of quadrilaterals one can form using these points is
1. 7C3
2. 7P3
3. 10 . 7C3
4. 420
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Correct Answer - Option 4 : 420

7C4 + 7C3 × 5C1 + 7C2 × 5C2 = 420

2. 7P3 = 2 × 7 × 6 × 5 = 420

Alter: 12C4 – (5C4 + 5C3 .7C1) = 495 – (5 + 70) = 420

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